* Phil may not have/want to support Linux; * Manipulating memory blocks is way faster than the RGBSurface; * Reading/Writing MemoryBlock.Byte() is going to be much faster than RGBSurface.Pixel() and RGB(x,y,z) * Plus, of course, access to Apple's VecLib functions, which are very fast. Many reasons to do so. Just wish there would be an easier way to do it.
-- dda fPic, a Picture replacement for console apps http://sungnyemun.org/?q=node/7 On 7/11/06, Maarten de Vries <[EMAIL PROTECTED]> wrote:
Of course, you can do what Charles explained. But you can also use Picture.RGBSurface.Pixel(x,y). Maybe you have a good reason to use a memoryblock, but I can't see it. It doesn't support Linux.... Maarten
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