Although I can conceive of a quantum computer 'bit' having three
states; unentangled-0, unentangled-1, and entangled-?
I can even conceive of making a memory element using a 4-bit A/D-D/A
converter that has 10 levels of quantization (0000-1001) though you'd
have to use a ridiculously large voltage to avoid the noise floor
between the quantized voltage levels (10 volt logic, anyone?) :) Though
you'd at least have a 'native' base-10 memory element (register) to do
computations on. Clearly impractical, though, even with Moore's law...
On Jul 28, 2006, at 2:29 PM, Mathieu Langlois wrote:
Wrong, anything digital uses base 2. It's just the nature of digital,
there is either electricity or there is not. When you start measuring
the level of the electricity, you enter the analog world.
On 7/28/06, Art Peters <[EMAIL PROTECTED]> wrote:
Calculators typically use base 10 calculations, computers typically
employ base 2. In base 2 the numbers here can't be represented
exactly because each term in the binary sequence (1/(2^n)) can only
get arbitrarily close to the number. In base 10 the number can be
represented exactly.
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William H Squires Jr
4400 Horizon Hill #4006
San Antonio, TX 78229
[EMAIL PROTECTED] <- remove the .nospam
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