[EMAIL PROTECTED] wrote:
Subject: Re: RE: my silly listbox
From: <[EMAIL PROTECTED]>
Date: Tue, 15 Aug 2006 8:10:48 -0400
I have tried putting the addrow inside the loop...
at the beginning and end of the loop statement...
and nothing...
AARGH....
<smile>
From: "Walter Purvis" <[EMAIL PROTECTED]>
Date: 2006/08/14 Mon PM 09:30:29 EST
To: "'REALbasic NUG'" <[email protected]>
Subject: RE: my silly listbox
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On
Behalf Of Bill Johnson
Sent: Monday, August 14, 2006 8:17 PM
To: REALbasic NUG
Subject: Re: my silly listbox
On 14-Aug-06, at 5:03 PM, [EMAIL PROTECTED] wrote:
>
> Here is my code....
>
> after it runs I am left with the number 20 in what I would
call cell
> 0,1
>
> Regards
>
> ========================
> dim i as integer
> me.HasHeading=true
>
> me.heading(0)="Heading1"
> me.Heading(1)="heading2"
>
> me.addrow""
>
> for i = 1 to 20
> me.Cell(0,0)=str(i)
> next i
Since:
> me.Cell(0,0)=str(i)
THE IMPORTANT PART HERE IS 0,0
you always fills the same Cell, what are you awaiting ?
Changing the AddRow is nice (mandatory), but:
For i = 1 To 20
// Add a brand new Row
Me.AddRow ""
// Get the just added Row #
locRow = Me.ListIndex
// Add the Index value
Me.Cell(i,0) = str(i) // *
// Place here a more usefull code
Next
* Totally useless, but if it let you understand...
will do something.
BTW: did you read the ListBox Control entry in the Language Reference ?
Cheers,
Emile
_______________________________________________
Unsubscribe or switch delivery mode:
<http://www.realsoftware.com/support/listmanager/>
Search the archives of this list here:
<http://support.realsoftware.com/listarchives/lists.html>
