Hi bob,
like this:
>> x: 5
== 5
>> debug 'x
x = 5
Regards
> Ladislav-
> I gave that a try and got:
>
> >> x: 5
> == 5
> >> debug: func [a] [print join a join " = " get a]
> >> debug x
> ** Script Error: get expected word argument of type: any-word.
> ** Where: print join a join " = "
>
> -bob
>
> >Hi,
> >
> >debug: func [a] [print join a join " = " get a]
> >
> >Regards
> > Ladislav
> >
> >
> > > I'm trying to set a quick debug function that I can throw in where
ever
> >I'm
> > > having trouble.
> > > first I have this:
> > >
> > > >> x: 5
> > > == 5
> > > >> print join 'x join " = " x
> > > x = 5
> > >
> > > then I wrote:
> > > >> debug: func [a b] [print join a join " = " b]
> > > >> debug 'x x
> > > x = 5
> > >
> > > All well and good but the key word here is quick and I type slow.
> > > What I want is:
> > >
> > > debug x
> > >
> > > I write:
> > >
> > > >> debug: func [a] [print join 'a join " = " a]
> > > >> debug x
> > > a = 5
> > >
> > > How do I get 'x out of a?
> > >
> > > This may not seem like much until you see the difference between:
> > >
> > > debug some_really_long_variable_name
> > > and
> > > debug 'some_really_long_variable_name some_really_long_variable_name
> > >
> > > -bobo
> > >
>
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