> ...but there's for sure a more elegant solution to it... >> b: [label1 [label2 [label3 [data1 label4 [data2]]]]] == [label1 [label2 [label3 [data1 label4 [data2]]]]] >> B/label1/label2/label3/label4 == [data2] Andrew Martin ICQ: 26227169 http://members.nbci.com/AndrewMartin/ -><- -- To unsubscribe from this list, please send an email to [EMAIL PROTECTED] with "unsubscribe" in the subject, without the quotes.
- [REBOL] [SCRIPT] select/deep CRS - Psy Sel/SPO, COUSSEMENT Christophe, CPN
- Andrew Martin
