> ...but there's for sure a more elegant solution to it...

>> b: [label1 [label2 [label3 [data1 label4 [data2]]]]]
== [label1 [label2 [label3 [data1 label4 [data2]]]]]
>> B/label1/label2/label3/label4
== [data2]

Andrew Martin
ICQ: 26227169 http://members.nbci.com/AndrewMartin/
-><-


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