Hi Joel 

Pollard Rho is great heuristic but neither a running time of O(N^.25) nor
success is in finding factors is guarenteed.  but I use it.
   

On Wed, 16 Jan 2002, Joel Neely wrote:

> Hi, all,
> 
> There was some discussion about factoring and primes a while back
> (don't remember exactly when).  Perusing my number theory books
> reminded me of Pollard's "rho" method, which typically finds
> factors *WAY* faster than the easier to understand and implement
> brute-force trial-divisors-in-order-up-to-the-square-root method
> we've probably all played around with.
> 
> A quick bit of REBOL hacking produced...
> 
>     rho: make object! [
> 
>         ; "randomizing" function across prime residue classes
> 
>         f: func [x [number!] n [number!]] [1.0 * x * x + 1 // n]
> 
>         ; greatest common divisor (helper first)
> 
>         _gcd: func [a [number!] b [number!] /local c] [
>             while [b > 0] [c: a // b   a: b   b: c]
>             a
>         ]
>         gcd: func [a [number!] b [number!]] [
>             a: abs a   b: abs b
>             _gcd max a b min a b
>         ]
> 
>         ; returns 1 or n for primes, some factor for composites
> 
>         test: func [n [number!] /local x y d g] [
>             n: abs n
>             either n > 3 [
>                 d: n + (x: 2) - (y: f x n) // n
>                 while [d > 0] [
>                     if 1 < g: gcd n d [return g]
>                     d: n + (x: f x n) - (y: f f y n n) // n
>                 ]
>                 1
>             ][
>                 n
>             ]
>         ]
> 
>         ; returns block with some factors or input number (if prime)
> 
>         factors: func [n [number!] /local d r] [
>             r: copy []
>             while [even? n] [append r 2   n: n / 2]
>             while [1 < d: test n] [append r d   n: n / d]
>             if 1 < n [append r n]
>             r
>         ]
>     ]
> 
> Which does things like:
> 
>     >> rho/test 11        == 1
>     >> rho/test 111       == 3
>     >> rho/test 1111      == 11
>     >> rho/test 11111     == 41
>     >> rho/test 111111    == 3
> 
> and
> 
>     >> rho/factors 11               == [11]
>     >> rho/factors 111              == [3 37]
>     >> rho/factors 1111             == [11 101]
>     >> rho/factors 11111            == [41 271]
>     >> rho/factors 111111           == [3 7 5291]
>     >> rho/factors 101010101        == [41 271 9091]
>     >> rho/factors 10010101001      == [109 15187 6047]
>     >> rho/factors 1001001001001    == [31 41 271 2906161]
> 
> Note that the factors are not necessarily produced in order; I
> also haven't verified that they will always be prime.  However
> they should show that the number is composite.
> 
> No guarantees, but have fun!
> 
> -jn-
> 
> -- 
> ; sub REBOL {}; sub head ($) {@_[0]}
> REBOL []
> # despam: func [e] [replace replace/all e ":" "." "#" "@"]
> ; sub despam {my ($e) = @_; $e =~ tr/:#/.@/; return "\n$e"}
> print head reverse despam "moc:xedef#yleen:leoj" ;
> -- 
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