Hello Tom,
> Tom Conlin wrote :
>
> a bit prettier
> do rejoin['tab_nbr "/" l "/" c ": " 20]
>
You're almost right but a small glitch appeared in your version. The final
one should be :
do rejoin["tab_nbr/" L "/" C ": " 20]
instead of my original one :
> > join join join join "tab_nbr/" L join "/" C ": " 20
> > which generates ==
> > "tab_nbr/2/1: 20" then the "do" word will do it like this.
> >
> > do join join join join "tab_nbr/" L join "/" C ": " 20
> >
Thanks for the "cue". As you can see below, even if I knew the effect of the
"reduce" word - when used alone, I didn't think to use it, at least in the
form you submitted me - that is with the combined "rejoin" word.
And the worst here is that when confronted with this face-to-face encounter
I quickly told myself : Wow! It could have been great if the "join" word had
been used with so many parameters as I had under the hand. I simply missed
it but be sure that next time I'll try harder !!!
But as I have grabbed your attention for a moment, can I submit you another
question which I also asked myself when confronted with this other coding
example I tried a couple of days ago while submitting it to a friend of mine
who want to start in REBOL - don't worry about the apparent difficulty level
for this intro to REBOL because he is already doing professional coding in
other programming languages and I was effectively comparing many ways to do
the same thing - assignment (multiple ones in this case) :
The original try was :
set [ 'n1 'n2 'total 'diff ] [ 15 25 n1 + n2 n2 - n1] <--
the error is pointing n1 as having no value
print [n1 n2 somme diff]
while trying to eval n1 + n2
The expected result was : 15 25 40 10
but I had to rearrange it according to one of these alternatives to get the
expected result :
a) set [ 'n1 'n2 ] [ 15 25 ]
set 'somme n1 + n2
set 'diff n2 - n1
b) set [ 'n1 'n2 ] [ 15 25 ]
set ['somme 'diff ] reduce [ n1 + n2 n2 - n1 ]
c) set [ 'n1 'n2 ] [ 15 25 ]
set ['somme 'diff ] compose [ (n1 + n2) (n2 - n1) ]
And the related question : Is there is a way for REBOL to assign many
variables simultaneously (that is in a pseudo-parallel form on the same line
instead of serializing them by putting them on many successive lines) like I
was able to do in the Lisp language with the LET (for parallel assignment)
and LET* (for serial assignment) statements.
I know this is just a purist question for academicians but I'd like to know
if this is possible or not with REBOL as it is now
Thanks,
Gerard.
> > But now that I can use real variable indexes with my array, am I
supposed to
> > use loops too just to get
> > any cell value initialized with something other than some constant like
the
> > series of values : 10, 20 , 30 , 40 50 and 60.
>
>
> I think yes
>
>
> > Would it not be simpler to have something like this :
> >
> > tab_nbr: array/initial/series [3 2] 10 60 10 where the start, stop
and
> > increment values would be respectively 10 60 and 10.
> >
> > IS this already possible in another way that I am not aware of ?
> >
> > While I am at it, I also tried to use the word "reduce" and a to-block
> > conversion instead of the word "do" but it seems that the refered object
> > (tab_nbr) is not in the same context.
> >
> > So is there a way to notify REBOL that we want it to share some valuable
> > information from a context to another one or do we have to define it for
the
> > global one, which in this case is not under my control
> >
> > Thanks to all for any clue if any,
> >
> > Gerard
> >
> >
> >
> >
> > ----- Original Message -----
> > From: "Gregg Irwin" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Sent: Wednesday, June 26, 2002 1:00 PM
> > Subject: [REBOL] Re: making objects from block content
> >
> >
> > > Hi Again,
> > >
> > > As an addenduem, it may not work at all in your case as LOAD will very
> > > likely not recognize numbers as valid set-words.
> > >
> > > --Gregg
> > >
> > >
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