Hi, Laurent,
Whenever possible, I suggest letting REBOL do the work for you...
See below.
Laurent Giroud wrote:
>
> What I am doing is very simple, I get string data and store it
> this way :
>
> trans: [
> ["09:33" "12.30" "1 270"] ; [string! string! string!]
> ["09:34" "12.31" "4 450"]
> ...
> ]
>
> and need to convert it (for faster manipulation later on) into :
> [
> [9:33 12.30 1270] ; [time! decimal! integer!]
> [9:34 12.31 4450]
> ...
> ]
>
The only tricky bit is the embedded space in the third element
of each triplet, but you already know how to deal with that!
>> trans: [
[ ["09:33" "12.30" "1 270"] ; [string! string! string!]
[ ["09:34" "12.31" "4 450"]]
== [
["09:33" "12.30" "1 270"]
["09:34" "12.31" "4 450"]]
Using the first two triplets of your sample data...
>> foreach row trans [
[ foreach item row [
[ foo: load trim/all copy item
[ print [item foo type? foo]
[ ]
[ ]
09:33 9:33 time
12.30 12.3 decimal
1 270 1270 integer
09:34 9:34 time
12.31 12.31 decimal
4 450 4450 integer
Unless the input uses some strange representation (e.g., embedded
spaces which must be removed) the REBOL lexical scanner will
recognize the data for you.
-jn-
--
; Joel Neely joeldotneelyatfedexdotcom
REBOL [] do [ do func [s] [ foreach [a b] s [prin b] ] sort/skip
do function [s] [t] [ t: "" foreach [a b] s [repend t [b a]] t ] {
| e s m!zauafBpcvekexEohthjJakwLrngohOqrlryRnsctdtiub} 2 ]
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