Yes it is faster than the other methods:

>> a: 2 b: 3 d: now/precise loop 500000 [t: (1x0 * a) + (0x1 * b)]
difference now/precise d
=3D=3D 0:00:00.187

>> a: 2 b: 3 d: now/precise loop 500000 [t: as-pair a b] difference
now/precise d
=3D=3D 0:00:00.281


> -----Original Message-----
> From: [email protected] [mailto:[email protected]] On Behalf
> Of Maxim Olivier-Adlhoch
> Sent: Wednesday, November 11, 2009 12:56 PM
> To: [email protected]
> Subject: [REBOL] Re: dynamic pairs
>=20
>=20
> and the fastest method is:
>=20
> p: (1x0 * a) + (0x1 * b)
>=20
>=20
> -MAx
>=20
> 2009/11/9 sqlab <[email protected]>:
> >
> > =3DA0>> p: =3DA0as-pair a b
> > =3D3D=3D3D 1x2
> >
> > is enough or
> >
> > =3DA0>> p: to-pair reduce [a b]
> > =3D3D=3D3D 1x2
> >
> >
> >
> > On 09.11.2009 14:00, Semseddin Moldibi [ Bircom ] wrote:
> >> p: make pair! as-pair a b
> >>
> >> should work.
> >>
> >>
> >>> Hi!
> >>> =3D3D20
> >>> I'd like to use variables in a make statement for creating pairs:
> >>> =3D3D20
> >>> a: 1
> >>> b: 2
> >>> p: make pair! [a b] does not work for me.
> >>> =3D3D20
> >>> tia
> >>> =3D3D20
> >>> Peter Bj=3D3DF6rk
> >>> =3D3D20
> >>> Schweizerische Depeschenagentur Ag
> >>> =3D3D20
> >>> L=3D3DE4ngassstrasse 7
> >>> CH-3012 Berne
> >>> =3D3D20
> >>> Tel-M: +41-31-775 9892
> >>> Tel-G: +41-31-309 3986
> >>> =3D3D20
> >>> E-Mail: [email protected]
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