On Tue, 17 Aug 2004, [ISO-8859-1] Jorge Acereda Maci=E1 wrote:

yes, you would need an either negative? ...


But there has been alot of work on a round function that does all that
and more. it should not be hard to find, and is slated to make it into th=
e
next major release.


> On 17/08/2004, at 8:32, Tom Conlin wrote:
>
> >
> >
> > the simplest way is
> >
> > n: to-integer (n / 2)
>
> But that fails for n=3D-1. It yields 0, an arithmetic shift should retu=
rn
> -1.
>
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