Hi Gregg,
On Tuesday, January 18, 2005, 9:02:32 PM, you wrote:
GI> find-Nth: func [
GI> "Returns the series at occurrence N of value or none."
GI> series [series!]
GI> value
GI> n [integer!]
GI> /local count pos
GI> ][
GI> count: 0
GI> parse series [
GI> some [
GI> to value pos: (
GI> count: count + 1
GI> if count = n [return pos]
GI> ) skip
GI> ]
GI> ]
GI> none
GI> ]
find-nth: func [
"Returns the series at occurrence N of value or none."
series [series!]
value
n [integer!]
/local pos
] [
if n = 1 [return find series :value]
n: n - 1
parse series [
n thru value to value pos:
]
pos
]
>> find-nth "aaa*bbb*ccc*ddd*eee*fff" "*" 1
== "*bbb*ccc*ddd*eee*fff"
>> find-nth "aaa*bbb*ccc*ddd*eee*fff" "*" 2
== "*ccc*ddd*eee*fff"
>> find-nth "aaa*bbb*ccc*ddd*eee*fff" "*" 3
== "*ddd*eee*fff"
>> find-nth "aaa*bbb*ccc*ddd*eee*fff" "*" 4
== "*eee*fff"
>> find-nth "aaa*bbb*ccc*ddd*eee*fff" "*" 5
== "*fff"
>> find-nth "aaa*bbb*ccc*ddd*eee*fff" "*" 6
== none
>> find-nth "aaa*bbb*ccc*ddd*eee*fff" "*" 7
== none
(Though I hoped that the IF N = 1 was not needed... :)
If the value is just a character, you can simplify things out:
find-nth: func [
"Returns the series at occurrence N of value or none."
series [any-string!]
value [char!]
n [integer!]
/local pos
] [
parse series [
n thru value pos: (pos: back pos)
]
pos
]
Regards,
Gabriele.
--
Gabriele Santilli <[EMAIL PROTECTED]> -- REBOL Programmer
Amiga Group Italia sez. L'Aquila --- SOON: http://www.rebol.it/
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