check the URL for islink=2 or islink=10 One is a link, the other one a reference..
On 22 Sep., 13:45, kimdezen <[email protected]> wrote: > give this a try (you might need to run it under a user account who has > SmartTree access) > > <IODATA loginguid="<loginguid>" sessionkey="<sessionkey>"> > <TREESEGMENT action="gototreereference" guid="<guid of list a>" > type="link"/></IODATA> > </CLIENT> > > you will get the following XML back > <IODATA><TREESEGMENTS> > <SEGMENT guid="43C7CC60F0A14AF0932DC260604243A2" > parentguid="8B513D8A60674DDCA433B56905D177C6" close="0" islink="2" > name="con_quicklinks" type="link" value="con_quicklinks:Home" > imagetype="28" expand="1" col1value="con_quicklinks:Home" > col1fontcolor="#0000ff" col2fontcolor="#ff8C00" col2value="" > col1fontweight="normal" col2fontweight="normal"></SEGMENT> > </TREESEGMENTS> > > just make sure that select the very last SEGMENT node in the result > set - the GUID attribute will be the value of list B. > > Good luck, > Kim > > On Sep 16, 1:24 am, angle shade <[email protected]> wrote: > > > I have one list A referenced to another list B. > > > Does anyone know how I can find the guid of B using RQL, once I have > > discovered, using RQL, that A is a reference? > > > I can see that if I knew B I could find out that A links to it by using > > ‘Showing Reference List’ RQL but I can’t see how to find B from A. > > > Any ideas? > > > Ta -- You received this message because you are subscribed to the Google Groups "RedDot CMS Users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/reddot-cms-users?hl=en.
