As what I had learned form IBM-developwork the param kernel in grub menu should be : kernel /boot/vmlinuz-2.4..... root=/dev/hdxx(or root=/LABEL=/ (I am not quite sure of the root param, as I always use /dev/hdb7 in manual;) but I found the menu generate by redaht8 or 9 is : kernel /vmlinuz-2.4...... root=......
I don't understand why it change to /vmlinuz.... But I think it may lead to my trouble; ------------------------------------------ here is my problem: I plus an other harddesk which contain a RH8 to a box that have a RH9. RH9 is in hdb, / is hdb7 and /boot is hdb6. rh8 is in hdc, it's / is hdc5 and /boot is hdc1; I want to boot in to RH9 : the gurb menu of RH9 gen by redhat is like this: root (hd0,5) (the hdb1 is a fat32 with winxp ,grub is in mbr) kernel /vmlinuz-2.4.20-8 ro root=/LABEL=/ initrd /initrd-2.4.20-8.img this can't boot correctly as I plus the hdc on the box, It told me multi / is found ,and stop in the syslog as many faild had been given before! well, I try to boot manual,I type this: root (hd0,5) kernel /boot/vmlinuz-2.4.20-8 root=/dev/hdb7 grub told me file not found If I try : kernel /vmlinuz-2.4.20-8 root=/dev/hdb7 it pass! then with the same initrd param It start to boot but with the same faild at the end! so how can I boot correctly it I had two hd with LABEL /? Any advice would be appreciate! winglion [EMAIL PROTECTED] 2003-06-08 -- redhat-list mailing list unsubscribe mailto:[EMAIL PROTECTED] https://www.redhat.com/mailman/listinfo/redhat-list
