On Fri, 2003-09-05 at 13:12, Patrick Nelson wrote:
> RH9
>
> Have a php page and I want the outcome of
>
> du -hs /var/spool/imap/$username | awk '{print $1}'
>
> however, username is (say) joe.user.example.com but the directory is
> joe^user^example^com
>
> Any sed or awk experts help me do this in one line? The output is
> simply the amount of space used by the user.
>
why not let php do it?
$newuser = preg_replace ("/\./","^", $username);
should be close.
Bret
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