> Any documentation that states this is a class B network is wrong. It is a
> class C.
>
> Here is the breakdown...
> Class Netmask Network Addresses
> A 255.0.0.0 0.0.0.0 - 127.255.255.255
> B 255.255.0.0 128.0.0.0 - 191.255.255.255
> C 255.255.255.0 192.0.0.0 - 223.255.255.255
>
> These are the defaults.
This explains a lot. After reading this, I stepped back to my original
reference below which I saved years ago from the internet:
---
Section 3: Private Address Space
The Internet Assigned Numbers Authority (IANA) has reserved the
following three blocks of the IP address space for private networks:
10.0.0.0 - 10.255.255.255
172.16.0.0 - 172.31.255.255
192.168.0.0 - 192.168.255.255
We will refer to the first block as "24-bit block", the second as "20-bit
block", and the third as "16-bit" block". Note that the first block is
nothing but a single class A network number, while the second block is a set
of 16 continuous class B network numbers, and the third block is a set of
255
continuous class C network numbers.
---
I actually misread it. When it specifies here 192.168.0.0 - 192.168.255.255,
AND that it is a 16 bit block, I thought it was a class B as I seemed to
have 255 * 255 combinations of addresses. But it specifically says on the
last sentence it is actually by default a Class C. A bit confusing as I
though a 16 bit block meant B Class.
My only excuse is I tried to read and understand it while I was still a
newbie years ago, and it 'stuck' in my head.
HOWEVER. Do Linux Servers/Win Clients actually KNOW this, or should the
netmask of 255.255.0.0 override this as the other kind repondents have said?
OR is the only way around it to add the route line to the Linux server (yes,
the Linux server acts as gateway to the Win clients)?
I guess next time I'll just try it both ways.
Thanks to all repondents for your time.
Edward.
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