db = 10 Log(P-out / P in) According to my slide rule, P out / P in would
be about .707 for 1.5 db .707 X 150 = 106 watts
Somebody correct me if I'm wrong.
Gary - K7NEY
----- Original Message -----
From: "w9mwq" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Tuesday, March 22, 2005 11:59 AM
Subject: [Repeater-Builder] Duplexer Loss Question
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> I am curious with a set of TX-RX duplexers at 1.5 insertion loss,
> input power of 150 watts, what would be the power output? Need to
> know, as I don't think they are tuned correctly, or something might
> be wrong here.
>
> Mathew
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> Yahoo! Groups Links
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