JK,

The coaxial sections coming off each antenna element is 35 Ohm coax at odd 
multiples of 1/4 wave length.

What this does with antenna element at 50 Ohms then 1/4 wl down the 35 Ohm 
cable it looks close to 100 Ohms looking into this cable.  Then you take 2 of 
these ant elements/35 Ohm coax in parallel and you get 50 Ohms at this 
junction.  If have 4 elements do the same for the other 2 and then make another 
to join these 2 again using 35 Ohm 1/4 wl coax.

The length of the 50 Ohm coax going from the tx/rx to this antenna input does 
not matter for SWR or impedance.  Only concern would be length and loss of 50 
Ohm cable.

73, ron, n9ee/r





>From: Jeff Kincaid <[EMAIL PROTECTED]>
>Date: 2008/03/05 Wed PM 11:24:35 CST
>To: [email protected]
>Subject: [Repeater-Builder] Re: DB 212-2 Harness info.

>                  
>OK John, just making sure.  I'm not familiar with the configuration of
>the antenna, but what you are saying makes sense.  I'm confused by the
>idea that the length doesn't matter, because that would imply that
>everything is 50 Ohms throughout, which doesn't seem to be the case.
>
>'JK
>
>--- In [email protected], "John Everson"
><[EMAIL PROTECTED]> wrote:
>>
>> --- In [email protected], "Jeff Kincaid" <jeffk@> 
>> wrote:
>> >
>> > I think this is just sloppy word choice, rather than a lack of
>> > understanding, but I've seen it a couple of times now so let me 
>> clear
>> > it up in any case.  Regarding velocity factor, it's a factor, so you
>> > want to multiply it.  Subtraction is not a part of the equation.
>> > 
>> > Say your free space length is 100 inches, and your velocity factor 
>> is
>> > 88%.  Your length in cable is then 88 inches:
>> > 
>> > 100 x 0.88 = 88
>> > 
>> > Regards,
>> > Jeff
>> > 
>> > --- In [email protected], "John Everson"
>> > <johneverson@> wrote:
>> > >
>> > > So if I understand correctly, the length of the 50 ohm sections 
>> is 
>> > > irrelevant, as long as they are equal? Also, is my previous 
>> > > assumption that the matching stub is just made of 35 ohm cable 
>> cut to 
>> > > 1/4 wavelength at the operating frequency minus the vel. factor 
>> > > correct?
>> > > 
>> > > Thans again for the help.
>> > > John
>> >
>> Hello Jeff.
>> 
>> You are correct. It was a poor choice of words on my part. I 
>> understand the theory of velocity factor. I am still not sure about 
>> the lengths involved with the harness. If the 50 ohm sections from 
>> the loops to the "tee" can be any length, (as long as they are the 
>> same) doesn't that affect the impedance at the tee? I will assume the 
>> impedance at the feedpoint of the loop is 200 ohms. If we use half 
>> wavelengths of coax between the loops, the feedpoint impedance will 
>> be repeated at the end of the cable to the tee. Is this correct? If 
>> so, when the loops are connected to the tee, we should see 100 ohms, 
>> then, the matching section brings us to about 50 ohms. 
>> 
>> Is this correct? Or am I out to lunch?
>> 
>> Is the matching section a quarter wave?
>> 
>> I need to dig out the antenna handbook and refresh. That is for 
>> certain.
>> 
>> Thanks.   John
>>
>
>            


Ron Wright, N9EE
727-376-6575
MICRO COMPUTER CONCEPTS
Owner 146.64 repeater Tampa Bay, FL
No tone, all are welcome.


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