2A-B solving for once for A and once for B.
Or, to make it more clear (maybe), the sum of your receiver and half the
difference between the two (IOW, the frequency directly half way between
two two others), and the sum of the full difference plus the paging
transmitter frequency.
Putting it another way which might be easier to understand: The
frequencies half way from your RX to the paging TX, and the frequency
twice as far from the two (in the direction of the transmitter)
Either way, it's all 2A-B:
2(151.140) - 157.740 = 144.540
2(157.740) - 170.940 = 144.540
Joe M.
Tim Sawyer wrote:
>
>
> I'll watch those. How did you calculate them?
> --
> Tim
> :wq
>
> On Aug 20, 2010, at 5:38 PM, MCH wrote:
>
>>
>>
>> Most likely suspects would be 151.140 and 170.940 MHz.
>>
>> Joe M.
>>
>> Tim Sawyer wrote:
>> > I have paging intermod from 157.740 Mhz. My receiver is on 144.540
>> Mhz. I'm 100% sure there is another transmitter involved in the mix
>> because sometimes the pager is transmitting and I have no interference.
>> >
>> > I have an intermod calculator program but it wants all the known
>> transmitters and the target receiver. But I need to solve for an
>> unknown transmitter. Is there a way to calculate the other possible
>> soruce(s)?
>> > --
>> > Tim
>> > :wq
>> >
>> >
>> >
>> > ------------------------------------
>> >
>> >
>> >
>> > Yahoo! Groups Links
>> >
>> >
>> >
>> >
>>
>
>
>
>
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