xyuanlu commented on a change in pull request #1362:
URL: https://github.com/apache/helix/pull/1362#discussion_r492326134
##########
File path:
helix-core/src/main/java/org/apache/helix/messaging/handling/HelixTaskExecutor.java
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@@ -919,9 +912,25 @@ public void onMessage(String instanceName, List<Message>
messages,
// discard the message. Controller will resend if this is a valid
message
throw new HelixException(String.format(
"Another state transition for %s:%s is in progress with msg:
%s, p2p: %s, read: %d, current:%d. Discarding %s->%s message",
- message.getResourceName(), message.getPartitionName(),
msg.getMsgId(), String.valueOf(msg.isRelayMessage()),
- msg.getReadTimeStamp(), System.currentTimeMillis(),
message.getFromState(),
- message.getToState()));
+ message.getResourceName(), message.getPartitionName(),
msg.getMsgId(),
+ String.valueOf(msg.isRelayMessage()), msg.getReadTimeStamp(),
+ System.currentTimeMillis(), message.getFromState(),
message.getToState()));
+ }
+ if (createHandler instanceof HelixStateTransitionHandler) {
+ // We only check to state if there is no ST task
scheduled/executing.
+ Exception err = ((HelixStateTransitionHandler)
createHandler).validateStaleMessage(true /*inSchedulerCheck*/);
+ if (err != null) {
+ throw err;
+ }
+ }
+ if (stateTransitionHandlers.containsKey(messageTarget)) {
Review comment:
Yes. We do a filtering first based on current state, and if the message
is stale, we will directly delete it. (and we will throw exception as well, but
not at the execution stage as before)
Although there is no existing bug complaining 2 valid new messages at the
same time, I think we should not assume there will be no duplicated messages so
we should still keep the 3rd check.
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