but is there a reason you had to use the lambda?
How could I have done that? Meta methods are static.
I am interested because this is my first real stab at anything like this.
Cheers
2008/11/7 Ayende Rahien <[EMAIL PROTECTED]>
> Also works but is there a reason you had to use the lambda? Why not just
> pass the string array directly?
>
>
> On Fri, Nov 7, 2008 at 4:08 PM, Paul Cowan <[EMAIL PROTECTED]> wrote:
>
>> I ended up fixing it this way:
>>
>> protected void SetBuildTargets(Func<string[]> tasksAction)
>> {
>> foreach(var task in tasksAction())
>> BuildTasks.Add(task);
>> }
>>
>> [Meta]
>> public static Expression tasks(params ReferenceExpression[] expressions)
>> {
>> var blockExpression = new BlockExpression();
>>
>> var arrayExpression = new ArrayLiteralExpression();
>>
>> for (var i = 0; i < expressions.Length; i++)
>> arrayExpression.Items.Add(new
>> StringLiteralExpression(expressions[i].Name));
>>
>> blockExpression.Body.Add(new ReturnStatement(arrayExpression));
>>
>> return new MethodInvocationExpression(
>> new ReferenceExpression("SetBuildTargets"),
>> blockExpression
>> );
>> }
>>
>> 2008/11/7 Ayende Rahien <[EMAIL PROTECTED]>
>>
>> As for documentation.The best resource for that are chapter 6 & chapter
>>> 12.
>>>
>>>
>>> On Fri, Nov 7, 2008 at 1:55 PM, dagda1 <[EMAIL PROTECTED]> wrote:
>>>
>>>>
>>>> >> You need to create a meta method that accepts a params of
>>>> ReferenceExpression.this will allow you to skip the strings.
>>>>
>>>> I can get this working for one task expression
>>>>
>>>> Like this for the DSL:
>>>>
>>>> install "horn":
>>>> description "This is a description of horn"
>>>> svn "https://svnserver/trunk";
>>>> #buildfile default.build
>>>> tasks one
>>>>
>>>> And this for the meta method:
>>>>
>>>> [Meta]
>>>> public static Expression tasks(ReferenceExpression expression)
>>>> {
>>>> var condition = new BlockExpression();
>>>>
>>>> var taskExpression = new StringLiteralExpression(expression.Name);
>>>>
>>>> condition.Body.Add(new ReturnStatement(taskExpression));
>>>>
>>>> return new MethodInvocationExpression(
>>>> new ReferenceExpression("SetBuildTargets"),
>>>> condition
>>>> );
>>>> }
>>>>
>>>>
>>>> I cannot work out how to handle an array of ReferenceExpressions as I
>>>> can only return 1 expression.
>>>>
>>>> Do I need to use a ListExpression or something?
>>>>
>>>> By the way the lack of documentation for this kind of thing is
>>>> frightenning. Without Rhino.DSL I would have been lost.
>>>>
>>>> Cheers
>>>>
>>>> Paul
>>>>
>>>>
>>>>
>>>>
>>>> On 6 Nov, 16:31, "Ayende Rahien" <[EMAIL PROTECTED]> wrote:
>>>> > LOL
>>>> >
>>>> >
>>>> >
>>>> > On Thu, Nov 6, 2008 at 6:06 PM, Paul Cowan <[EMAIL PROTECTED]>
>>>> wrote:
>>>> > > Excellent,
>>>> >
>>>> > > I'll resist the urge to say that you should write a BOOk about this,
>>>> I'm
>>>> > > guessing you may have heard it before!!!
>>>> >
>>>> > > 2008/11/6 Ayende Rahien <[EMAIL PROTECTED]>
>>>> >
>>>> > > You need to create a meta method that accepts a params of
>>>> > >> ReferenceExpression.this will allow you to skip the strings.
>>>> > >> The meta method will be responsible only for translating the call
>>>> from RE
>>>> > >> to strings, and generating a new method call to the real Tasks
>>>> method
>>>> >
>>>> > >> On Thu, Nov 6, 2008 at 7:25 AM, dagda1 <[EMAIL PROTECTED]> wrote:
>>>> >
>>>> > >>> I have the following dsl with the help of rhino DSL
>>>> >
>>>> > >>> Install "component":
>>>> > >>> Description "blah"
>>>> > >>> Svn "https://server.com";
>>>> > >>> Tasks "one", "two", "three"
>>>> >
>>>> > >>> I am unhappy with it because I think I am over using strings.
>>>> >
>>>> > >>> Can anyone suggest a better way?
>>>> >
>>>> > >>> Also can anyone tell me how to read in the multiple values for the
>>>> > >>> tasks
>>>> > >>> Section on the last line?
>>>> >
>>>> > >>> Cheers- Hide quoted text -
>>>> >
>>>> > - Show quoted text -
>>>>
>>>>
>>>
>>>
>>>
>>
>>
>>
>
> >
>
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