Thanks Sean, Now I know that I can't find the memory occupied by a particular bucket/key in the riak cluster...I just cleared data directory in my local system and inserted that single bucket/key in my local system,So, no cluster in this scenario as I was running on a single node. The statistics showed me it occupied 2.6MB when I performed du -h on eleveldb directory(running in my local) and I didn't change n_val, so by default it should take 3. Then, Will a single node riak still replicates to three different locations(vnodes) as my n_val=3 and if the above is true, then the memory occupied by my bucket/key's data is 2.6/3 = 0.8666MB. Since, there is a single bucket with single key is available from my local Riak. Am I right?
Thanks, Venkatesh On Wed, Nov 28, 2012 at 7:36 PM, Sean Cribbs <[email protected]> wrote: > Venki, > > Regarding your original question about size of individual buckets/keys > within that data directory -- that cannot be done without directly > manipulating the storage engine or other components of Riak. One of the > benefits of Riak's consistent hashing is that you get a really even spread > among nodes and you don't really know (without digging into the Erlang > console) where specific keys live. That said, we have done it for customers > who have had specific production issues related to large keys, but this is > not something we recommend doing in general. > > > On Wed, Nov 28, 2012 at 1:59 AM, Venki Yedidha < > [email protected]> wrote: > >> Thanks Mark, >> >> Now when I performed du -h on the eleveldb directory in my local: It >> showed me some thing like: >> >> 4.9M ./1370157784997721485815954530671515330927436759040 >> 2.7M ./776422744832042175295707567380525354192214163456 >> 2.7M ./525227150915793236229449236757414210188850757632 >> 2.7M ./959110449498405040071168171470060731649205731328 >> 3.3M ./1073290264914881830555831049026020342559825461248 >> 2.7M ./1438665674247607560106752257205091097473808596992 >> 2.8M ./91343852333181432387730302044767688728495783936 >> 2.8M ./1324485858831130769622089379649131486563188867072 >> 2.7M ./228359630832953580969325755111919221821239459840 >> 2.9M ./890602560248518965780370444936484965102833893376 >> 2.8M ./913438523331814323877303020447676887284957839360 >> 2.6M ./639406966332270026714112114313373821099470487552 >> 2.7M ./159851741583067506678528028578343455274867621888 >> 177M . >> >> So, It occupied 177MB in total.. Now, My interest is I would like to know >> the space occupied by a particular bucket/key, Can I extract that >> information form the above? >> >> and how are these numbers like >> "776422744832042175295707567380525354192214163456" generated? >> >> Thanks, >> Venkatesh >> >> >> >> On Wed, Nov 21, 2012 at 5:24 AM, Mark Phillips <[email protected]> wrote: >> >>> Hi Venki >>> >>> On Sun, Nov 18, 2012 at 10:11 PM, Venki Yedidha >>> <[email protected]> wrote: >>> > Hi All, >>> > I would like to know the data storage of my riak database till >>> date. >>> > Also, I would like to know the space occupied on a riak cluster by a >>> > bucket/key's data inserted. am running all the nodes(in the cluster) on >>> > eleveldb backend. >>> > >>> >>> The easiest way to do this would be to run some flavor of "du" on the >>> backend directory that lives under /data of each of your Riak nodes. >>> The sum of all of the nodes should give you the total replicated data >>> set. Divide it by your n_val to get the actual data set size. >>> >>> Hope that helps. >>> >>> Mark >>> >>> > >>> > Thanks, >>> > Venkatesh >>> > >>> > >>> > >>> > _______________________________________________ >>> > riak-users mailing list >>> > [email protected] >>> > http://lists.basho.com/mailman/listinfo/riak-users_lists.basho.com >>> > >>> >> >> >> _______________________________________________ >> riak-users mailing list >> [email protected] >> http://lists.basho.com/mailman/listinfo/riak-users_lists.basho.com >> >> > > > -- > Sean Cribbs <[email protected]> > Software Engineer > Basho Technologies, Inc. > http://basho.com/ > >
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