On 11/29/06, Florin Malita <[EMAIL PROTECTED]> wrote:
a=$((a + 1))
si ca sa-mi aduc si eu contributia pretioasa la acest bikeshed, : $((a++)) e mult mai elite decit a=$((a + 1)) _______________________________________________ RLUG mailing list [email protected] http://lists.lug.ro/mailman/listinfo/rlug
