... as putea pune de ex.: > > eth0 - 192.168.0.1/24 > > eth0:0 - 192.168.0.10/24 > > eth0:1 - 192.168.0.100/24 ?
----- Original Message ----- From: "KobrAs" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Friday, July 04, 2003 9:22 PM Subject: [rlug] Re: IP > iptables -A OUTPUT -m owner --uid-owner 501 -s 192.168.0.1/24 -d any/0 -j > ACCEPT #501 = uid la user > > nu stiu sigur daca merge... dar sper sa te ajute cu ceva, daca nu vezi man > iptables / owner > > > Regards, > > Rotariu Bogdan - Information Technology > Alterox Sistem > www.alterox.ro > phone: +40740140301 > Where do you want to go tomorrow ? > > ----- Original Message ----- > From: "Irimia Suleapa" <[EMAIL PROTECTED]> > To: <[EMAIL PROTECTED]> > Sent: Friday, July 04, 2003 9:04 PM > Subject: [rlug] IP > > > > Salut. > > Problema: Sa presupunem urmatoarea situatie: > > > > eth0 - 192.168.0.1/24 > > eth0:0 - 192.168.10.1/24 > > eth0:1 - 192.168.100.1/24 > > ---------------------------- > > ls -la /home > > drwx------ 12 user1 user1 4096 iul 3 18:04 user1 > > drwx------ 5 user2 user2 4096 ian 19 23:41 user2 > > drwx------ 22 user3 user3 4096 iul 2 15:17 user3 > > ----------------------------- > > > > Se poate face in asa fel incat atunci cand: > > - user1 se logheaza, sa iasa pe internet cu ip-ul interfetei eth0 > > - user2 se logheaza, sa iasa pe internet cu ip-ul interfetei eth0:0 > > - user3 se logheaza, sa iasa pe internet cu ip-ul interfetei eth0:1 ? > > > > Multumesc. > > > > > > > > > > > > >
