Daca vrei sa le dai voie in functie de mac poti incerca:

1)faci un fisier ex:mac_address in care treci ip-urile si mac-urile
ex: 192.168.1.15 xxxxxxxxxxxx
2)next arp -f /cale/mac_address

Eu am incercat si a mers.

----- Original Message ----- 
From: "Marius Stan" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, June 11, 2004 10:36 AM
Subject: [rlug] Re: Te rog mult sa ma ajuti intr-o problema de linux


> [EMAIL PROTECTED] wrote:
> 
> >Am incercat scriptul, dar primesc msg-ul acesta de eroare:
> >172.27.37.2
> >iptables v1.2.8: Bad mac address `172.27.37.2'
> >Try `iptables -h' or 'iptables --help' for more information.
> >00:0D:61:94:5E:6C
> >iptables v1.2.8: host/network `00:0D:61:94:5E:6C' not found
> >Try `iptables -h' or 'iptables --help' for more information.
> >172.27.37.3
> >iptables v1.2.8: Bad mac address `172.27.37.3'
> >Try `iptables -h' or 'iptables --help' for more information.
> >00:0D:61:94:5E:6A
> >iptables v1.2.8: host/network `00:0D:61:94:5E:6A' not found
> >Try `iptables -h' or 'iptables --help' for more information.
> > Fisierul cu ip-uri si mac-uri ar avea sintaxa asta: ip<tab>mac
> >Ce am gresit?
> >
> >Poti incerca ceva de genul:
> >
> >for i in `cat /etc/fisierul_tau_cu_ip_uri_si_macuri`; do
> >ip=`echo $i | cut -d\  -f1`;
> >mac=`echo $i | cut -d\  -f2`;
> >  
> >
> asa merge ? (f1 inversat cu f2)
> 
> ip=`echo $i | cut -d\  -f2`;
> mac=`echo $i | cut -d\  -f1`;
> 
> 
> 
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> 

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