It's because the function is a pointer, ever tried to use capatilize twice in a function call like that? Does the exact same thing, and I forget how you fix it, only know why it does that.
----- Original Message ----- From: "Hiddukel" <[EMAIL PROTECTED]> To: <[email protected]> Sent: Wednesday, February 11, 2004 9:21 PM Subject: Format Number function > I have a function that I got from a snippet that I need a little help with. > It seems to work fine the first time it is called but not the second time. > Here is the code I was using to test it with: > > printf_to_ch(ch, "Your current balance is: %s Steel and %s Gold.\n\r", > fnum(1000), fnum(2000)); > > What this outputs is: > > Your current balance is: 1,000 Steel and 1,000 Gold. > > When it should be: > > Your current balance is: 1,000 Steel and 2,000 Gold. > > Here is the fnum function in question: > > char *fnum(long number) > { > int index,index_new,rest; > char buf[16]; > static char buf_new[16]; > > sprintf(buf, "%ld", number); > rest = strlen(buf)%3; > > for (index = index_new = 0;index < strlen(buf); index++, index_new++) > { > if (index != 0 && (index - rest) %3 == 0 ) > { > buf_new[index_new]=','; > index_new++; > buf_new[index_new] = buf[index]; > } > else > buf_new[index_new] = buf[index]; > } > buf_new[index_new] = '\0'; > return buf_new; > } > > Any help on this would be very much appreciated. > > > > > -- > ROM mailing list > [email protected] > http://www.rom.org/cgi-bin/mailman/listinfo/rom
