You don�t stop it. But another method m2() in SuperClass can�t be accessed, while it isn�t implemented in CommonMethodsImpl.
mit freundlichen Gr��en
Jan Mat�rne
RZF NRW
Sachgebiet 314-P Methodenberatung
Internet: [EMAIL PROTECTED]
-----Urspr�ngliche Nachricht-----
Von: [EMAIL PROTECTED] [SMTP:[EMAIL PROTECTED]]
Gesendet am: Freitag, 4. Januar 2002 10:57
An: [EMAIL PROTECTED]
Betreff: Re: AW: (ROSE) Question Export control of Method
Wichtigkeit: Hoch
in response to Jan...
but how would u still stop the an instance of the child class
Sub from calling the inherited m1() method?
i am not sure the original question is a valid one in the first place? how is
it possible that a method declared public/protected by a parent class be NOT
accessible by child class?
this would throw the entire concept of inheritance out of the window?
Anil, are you sure u have got ur requirements correctly mapped?
best,
-Piyush
_________________________Reply Separator_________________________
Jan Materne wrote:
OK: you want to have methods in a (super)class which can be
accessed by "normal" classes but can't by subclasses?
As far as I know, there is no (direct) way. But you can use
"delegation" for it:
public interface CommonMethods {
public int m1(int a);
}
public class CommonMethodsImpl implements CommonMethods {
public int m1(int a) {
// Implementation goes here
return a;
}
}
public class Super implements CommonMethods {
// for delegation
private CommonMethods cm = new CommonMethodsImpl();
// the delegation
public int m1(int a) {
return cm.m1(a);
}
}
public class Sub extends CommonMethods {
// normal implementation
}
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