Re: Client debug?

[Lars Widmer]

Hello!
Jim, I once used the following code:
***
import java.net.*;
import java.io.*;
public class httpviewer
   {
   public static void main(String[] asArgs)
       {
       try
           {
           ServerSocket ss = new ServerSocket(8899);
           Socket s = ss.accept();
           InputStream is = s.getInputStream();
          
           while(true)
               {
               int i = is.read();
               if (i==-1) break;
               System.out.write(i);
               }
              
           System.out.println("\n\nConnection closed");
           }
       catch(IOException ioe)
           {
           System.err.println("Exception:");
           ioe.printStackTrace();
           }
       }
   }
***
It shows the lines which the client sends in order to make a call. They 
look about the following HTTP-Request:
POST / HTTP/1.1
Content-Length: 127
Content-Type: text/xml
User-Agent: Java1.4.0_01
Host: dskt5591:8899
Accept: text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2
Connection: keep-alive

As an other try I used a tool like
"EffeTech HTTP Sniffer"
That was better, but it didn't show all.
I got the following HTTP-Response:
HTTP/1.1 200 OK
Server: Apache XML-RPC 1.0
Connection: close
Content-Type: text/xml
Content-Length: 135
At the end I had what I wanted :-)
More I haven't... Sorry
Lars


Jim Tay wrote:

Hi,

Is there a way to see the actual xml that XmlRpcClient generates on an
execute call?  I can't find any debug functions in this class...
(I'm using the libraries in xmlrpc-1.1.jar)

Thanks,
Jim Tay


 



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