Sancar Adali wrote: > I'm trying to access and update a particular element of a matrix to update it > > for example in R, > > mat=matrix(0,nrow=2,ncol=2) > mat[0,0]= mat[0,0]+1
In R, vector indexing starts at one; zero are silently ignored. > How do I do this in rpy2 > do I have to use the low-level interface or can I use high-level interface > Using the high-level interface is possible. One way is: import rpy2.robjects as ro m = ro.r['matrix'](range(4), nrow=2, ncol=2) idx = ro.IntVector([1,1]) m2 = m.assign(idx, 33) print(m2) Not as elegant as one could wish... the 2.1 series for rpy2 will hopefully have something nicer. L. PS: using the rpy2-numpy compatibility layer is an another way. ------------------------------------------------------------------------------ Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H _______________________________________________ rpy-list mailing list rpy-list@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/rpy-list
