With rpy2 (although there is currently no formal class for factors):
import rpy2.robjects as ro
vec = ro.StrVector(("a", "b", "a", "b"))
vec = ro.r["factor"](vec)
On Thu, 2009-04-09 at 19:38 -0400, David Warde-Farley wrote:
> Hi all,
>
> I'm somewhat new to Rpy, and trying to use the R random forests
> package from Python, and depending on the type it receives for one
> variable it switches behaviour. If I want it to do classification it
> expects a "factor" for y, but I am at a loss for the easiest way to
> call convert a python list to a factor that I can use in a call to
> r.randomForest().
>
> I suppose I could also use r('randomForest(...)') but that could would
> require appropriately converting data matrices, etc. to text literals
> that R can handle, which seems both a bit wasteful memory-wise (I'm
> sure RPy already does this at some point) and non-obvious how to do
> it.
>
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