Use the method .rx2()
http://rpy.sourceforge.net/rpy2/doc-2.2/html/vector.html?highlight=rx2#extracting-r-style

There is a section on S4 objects in the documentation that happen to use 
lme4 as an example.
http://rpy.sourceforge.net/rpy2/doc-2.2/html/robjects_oop.html?highlight=lme4#s4-objects





On 10/5/10 2:13 AM, BB wrote:
> I realized I can have R seperate out the result. So I have
>
> robjects.r('M0 = lmer (y ~ 1 + (1 | county))')
> res = robjects.r('coef(M0)')
>
> coef function returns the detailed result. From this
>
> print res.rclass
> print res.r_repr()
>
> I get
>
> <rpy2.rinterface.SexpVector - Python:0xb78ccee0 / R:0xc45a040>
> structure(list(county = structure(list("(Intercept)" = c(1.06750311717691,
> 0.887536167587372, 1.23038235347237, 1.22454371552118, 1.28997542657877,
> ...
> ...
> 1.43258359311308, 1.40791697459764, 1.49612123813243, 1.28341119552016
> )), .Names = "(Intercept)", row.names = c("AITKIN", "ANOKA",
> "BECKER", "BELTRAMI", "BENTON", "BIG STONE", "BLUE EARTH", "BROWN",
> ...
> "WINONA", "WRIGHT", "YELLOW MEDICINE"), class = "data.frame")), .Names =
> "county", class = "coef.mer")
>
> How can I access this? It is reported to be as SexpVector, but res[0] gives me
> the same thing as str(res).
>
>
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experiences on the web. Be a part of the beta today.
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