Hey , i am new to rpyc 3 , and i have a question. I want to start a threaded server on my own socket implementation (i am using an adress family that python not supports) - what is the right way to do this ?
currently my code looks like this ----------------------------------------------------------------------------------------------------------- from rpyc.utils.server import ThreadedServer my_binded_socket = my_special_socket_factory( ....) # I use dummy host - and port just to create a threaded server. server = ThreadedServer(rpyc.SlaveService, hostname="127.0.0.1",port=5555) # than i replace the listener with the socket i created before. server.listener = my_binded_socket server.start() ------------------------------------------------------------------------------------------------------------- I must say that this way works fine - but its hacky and i think that there must be a better way to this. So Is there?
