Thanks Tomer,
Just investigating further and it was already running. Operator error
yet again! In my defence it was quite late last night. All working
fine now.
Sorry!
Mick
On 31/07/12 08:52, Tomer Filiba wrote:
it seems you're already running an rpyc server on that port (or at
least another python process, which would be odd unless it's another
rpyc server).
to change the port just run
$ ./rpyc_classic.py -p 12345
where 12345 is the port to use. see --help
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On Tue, Jul 31, 2012 at 2:21 AM, Mick Sulley <[email protected]
<mailto:[email protected]>> wrote:
Hi Tomer,
Thanks for the fast reply.
control@pia /usr/local/src/rpyc-3.2.2 $ sudo netstat -nap | grep 18812
tcp 0 0 0.0.0.0:18812 <http://0.0.0.0:18812>
0.0.0.0:* LISTEN 6274 <tel:6274>/python
control@pia /usr/local/src/rpyc-3.2.2 $
Sorry but I am not too sure what that means. How do I change the
port number?
As far as I know there is no firewall on the Pi.
Cheers
Mick
On 30/07/12 23:50, Tomer Filiba wrote:
interesting. either it's already in use, which would be strange
(TCP 18812) or the kernel has a more limited TCP port space (on
this limited device) -- but that would be very strange.
try running
sudo netstat -nap | grep 18812
to see who's taking it
if that won't help, try changing the port to a lower number, say,
8812 <tel:8812>.
btw, the pi doesn't have any firewalls on it, right?
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On Tue, Jul 31, 2012 <tel:2012> at 1:44 AM, Mick Sulley
<[email protected] <mailto:[email protected]>> wrote:
Hi,
I am trying to use rpyc on my Raspberry Pi running Raspian.
When I try to run rpyc_classic.py I get an error
control@pia /usr/local/src/rpyc-3.2.2 $ sudo rpyc_classic.py
Traceback (most recent call last):
File "/usr/local/bin/rpyc_classic.py", line 171, in <module>
main()
File "/usr/local/bin/rpyc_classic.py", line 167, in main
handler(options)
File "/usr/local/bin/rpyc_classic.py", line 122, in
serve_threaded
auto_register = options.auto_register)
File
"/usr/local/lib/python2.7/dist-packages/rpyc/utils/server.py", line
76, in __init__
self.listener.bind((hostname, port))
File "/usr/lib/python2.7/socket.py", line 224, in meth
return getattr(self._sock,name)(*args)
socket.error: [Errno 98] Address already in use
control@pia /usr/local/src/rpyc-3.2.2 $
Have I done something wrong here? I am far from an expert so
it is quite possible I have made a stupid mistake. I did try
installing 3.2.0, which I have running on an Ubuntu server,
but that gave the same problem.
Any ideas?
Thanks
Mick
