Why 3600, if it's five minutes? Wouldn't it be divided by 300? And even if the right divisor is 3600, how do I get a value less than 2.7e-04 (but larger than 0), if I'm only giving it integers.
Steve Robb wrote: >Think of it this way, if you have a measurement of 10 units in a 5 minute >period you think you would have the value 10 stored but the per second rate >would actually be 10/3600 = 2.7e-03. That's the value that gets stored since >everything gets stored as a per second rate. > >MAX and LAST won't change the stored value, just the way it's aggregated. > >Steve Robb > > > > -- Unsubscribe mailto:[EMAIL PROTECTED] Help mailto:[EMAIL PROTECTED] Archive http://www.ee.ethz.ch/~slist/rrd-users WebAdmin http://www.ee.ethz.ch/~slist/lsg2.cgi
