On Oct 03, "Serge Maandag" wrote:

> Because you defined this RRA:
>       RRA:AVERAGE:0.5:1:18
> 
> Which will only hold the last 18 samples. It was adequate for the
> example you gave earlier on, but if you want to graph a full week, you
> must think more in the lines of:
> 
> 1 week = 7 days = 7*24 hours = 7*24*3600 secs = 311040000 secs.
> Sample time = 900 secs
> 
> No of rows to keep = 311040000/900 = 345600 rows
> That would make:
>       RRA:AVERAGE:0.5:1:345600
> 
> That are a lot of rows. Only useful if you are generating graphs 345600
> pixels wide.
> I would consolidate more than 1 primary point into a consolidated point
> (=row).
> 
> Say your graph will be 600 pixels wide. Then 600 rows will be enough.
> So take the average of 345600/600 = 576 primary datapoints per row:
>       RRA:AVERAGE:0.5:576:600

I get it.  Thanks very much.  I have it working well.

Mike

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