On Thu, Oct 12, 2006 at 03:03:05PM +0200, Heiko Teichmann wrote: > > Each time an interval is computed, it is fed to every RRA. When an > > RRA has enough data to generate a new row, it will do so.
> Did that mean that even the RRA with the large pdp_per_row (288) stores > the data for the 288 steps and computes then the new row for the RRA? If > so what would be the divisor for the average computing if some data > failing (e.g. 2 steps fails -> 286 data points available all with the > same value; Question: average = (286*x)/288 or (286*x)/286 )? I believe the answer to be (286*x)/286. Shouldn't be hard to verify in an experiment. -- Alex van den Bogaerdt http://www.vandenbogaerdt.nl/rrdtool/ -- Unsubscribe mailto:[EMAIL PROTECTED] Help mailto:[EMAIL PROTECTED] Archive http://lists.ee.ethz.ch/rrd-users WebAdmin http://lists.ee.ethz.ch/lsg2.cgi
