> With 1.1.1 you can do this: > > Given "$n_users in the system" do |num_users| > case num_users > when "a user" > # one user case > when /(\d*) users/ > # multi user case using $1 > end > end > > With 1.1.2 you can do this: > > Given /(a|\d*) users? in the system/ do |num_users| > num_users = (num_users == 'a') ? 1 : num_users.to_i > (1..num_users).each do > # ... > end > end
Didn't know you could do that! Thanks. So, the step will yield all the matches in the same order regexp will populate the matches array? Regards, kamal _______________________________________________ rspec-users mailing list rspec-users@rubyforge.org http://rubyforge.org/mailman/listinfo/rspec-users
