ooops, that sent itself early...
. . .
there are other entries in the hash so presumably I will need something like
this
foo.should_receive(:bar) do |hash|
actual = hash[:some_key]
*hash[:some_key] = nil*
hash.should == {
:my => 'expected'
:other => 1
:ields => :in_the_hash
}
actual.should =~ [1,2,3]
end
i.e. I assert :some_key and 'the rest' separately.
There isn't a way to do this simpler is there?
Thanks again David!
On Tue, Feb 1, 2011 at 8:46 AM, James OBrien <[email protected]> wrote:
> Awesome, thanks David!
>
> there are other entries in the hash so presumably I will need something
> like this
>
> i.e.
>
>
> foo.should_receive(:bar) do |hash|
> actual = hash[:some_key]
>
> hash[:some_key].should =~ [1,2,3]
> hash.shoul
> end
>
>
>
>
> On Tue, Feb 1, 2011 at 4:43 AM, David Chelimsky <[email protected]>wrote:
>
>>
>> On Feb 1, 2011, at 3:40 AM, James OBrien wrote:
>>
>> hey, thanks for reading:
>>
>> I have a problem which can be reduced to this,
>>
>> from within an example of mine I call the helper 'expect_call' which is
>> defined thus:
>>
>> def expect_call(*hash*)*
>> *obj.should_receive(:some_
>> method).with(*hash*)*
>> *end
>>
>> and in one of my examples the 'expected' hash is strictly defined as
>> follows
>>
>> expect_call(*{
>> :some_key => [1,2,3]
>> }*)
>>
>> however my spec fails because it is actually called with
>>
>> *{
>> :some_key => [1,3,2]
>> }
>>
>> *or maybe
>>
>> *{
>> :some_key => [2,3,1]
>> }
>>
>> *or
>>
>> *{
>> :some_key => [2,1,3]
>> }
>>
>> *i.e. the array part is not in the order i 'expect' BUT i don't actually
>> care about the order. So I would like to be able to change my one example to
>> something like this:
>>
>> expect_call(*{
>> *:some_key => [1,2,3]*.ignoring_order
>> }*)
>>
>> does such a concept exist or do I have to change the implementation of
>> expect_call to use some sort of custom matcher - I am reluctant to do this
>> since this method is called in other cases where maybe (for arguments sake)
>> I DO care about array ordering within the hash.
>>
>>
>> rspec-expectations lets you do this:
>>
>> foo.bar.should =~ [1,2,3]
>>
>> This passes as long as the array contains exactly those three elements in
>> any order. You can use this now in conjunction with rspec-mocks, like this:
>>
>> foo.should_receive(:bar) do |hash|
>> hash[:some_key].should =~ [1,2,3]
>> end
>>
>> It's a bit more verbose than what you're looking for, but it can get you
>> there with rspec as/is today.
>>
>> Going forward, we might want to consider an array_including argument
>> matcher for rspec-mocks. We already have a hash_including matcher that works
>> like this:
>>
>> foo.should_receive(:bar).with(hash_including(:a => 'b'))
>>
>> Similarly we could have:
>>
>> foo.should_receive(:bar).with(array_including(1,2,3))
>>
>> The only problem with this is the name: array_including could mean
>> different things (ordered/unordered, only these elements or subset, etc).
>> The hash_including matcher is specifically about a subset of a hash. But
>> perhaps we could extend this with something like you proposed above:
>>
>> foo.should_receive(:bar).with(array_including(1,2,3))
>> foo.should_receive(:bar).with(array_including(1,2,3).ingoring_order)
>>
>> foo.should_receive(:bar).with(array_including(1,2,3).only.ingoring_order)
>>
>> The thing is, I'm not sure this is any better than the example I gave
>> above, which is very precise and works today. Thoughts/opinions welcome.
>>
>> Hope someone can solve this for me - MUCH appreciation.
>>
>>
>> As an aside, when passing a hash as an argument you don't need to use
>> curly braces, as long as the hash is the last argument to the method. These
>> two are equivalent:
>>
>> expect_call(1, :a, {:some_key => 'some value'})
>> expect_call(1, :a, :some_key => 'some value')
>>
>> HTH,
>> David
>>
>>
>>
>>
>> _______________________________________________
>> rspec-users mailing list
>> [email protected]
>> http://rubyforge.org/mailman/listinfo/rspec-users
>>
>
>
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