Assuming I understand your pseudocode correctly, your example would be
written like this:
``` ruby
RSpec.describe "foo" do
it "bar" do
puts 1
end
describe "baz" do
it "quux" do
puts 2
end
puts 3
end
end
```
This would print the numbers in the following order:
3
1
2
...which, noticably, is different from the order of mocha. I can't comment
on Mocha's design (having never used it) but for RSpec, we intentionally
load all the specs first (which involves evaluating the `describe` blocks),
then apply spec ordering, filtering, etc, and then run the specs (the `it`
blocks). Thus, the `3` is printed first (as it got printed while specs
were being defined) and then the specs ran and 1 and 2 are printed.
HTH,
Myron
On Thu, Apr 21, 2016 at 9:50 AM, <[email protected]> wrote:
> Hi,
>
> I'm a current maintainer of Mocha <https://mochajs.org>, which (AFAIK)
> was inspired by RSpec. I am not the *author *of Mocha; the author is
> long gone, or I'd ask him about this.
>
> My question regards a paradigm which seems common to BDD-style test
> frameworks. I assume that RSpec works similarly, but I apologize if I'm
> incorrect.
>
> It's most easily illustrated with a pseudocode example (sorry, I'm
> unfamiliar with Ruby):
>
> begin suite 'foo'
>
> begin test 'bar'
> print 1
> end test
>
> begin suite 'baz'
>
> begin test 'quux'
> print 2
> end test
>
> print 3
>
> end suite
> end suite
>
>
> In Mocha (and I assume RSpec), the following would be printed:
>
> 1
> 3
> 2
>
>
> This is difficult for some users to reason about. I'm unable to explain
> what this algorithm buys us, other than perhaps better control over
> disabling tests and suites. Can anyone explain why it works as it does?
>
> thanks
> Chris
>
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