On Tue, 31 Oct 2006, Jason Cox <[EMAIL PROTECTED]> wrote:
> Hi all,
> I have the following in a cron job
> /usr/bin/rsync -ub --suffix=~$(date +%F) /Data/Jobs/ /Data/Backups/Jobs/
> -razv --no-whole-file --ignore-errors partial
>
> Problem is that when the command is run on the command line everything
> works. However, when its in a cron job it fails with the following,
>
> /bin/sh: -c: line 0: unexpected EOF while looking for matching `)'
> /bin/sh: -c: line 1: syntax error: unexpected end of file
>
> Anyone seen this before or able to put some light on the problem?
Cron treats '%' as a special character. From the crontab man page:
The sixth field of a line in a crontab file is a string that
is executed by the shell at the specified times. A percent
character in this field (unless escaped by \) is translated
to a NEWLINE character.
HTH.
John
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