Ewe da man Slef.  Reading that just gave me a headache. LOL
Joe
The study of history is a powerful antidote to contemporary arrogance. It is
humbling to discover how many of our glib assumptions, which seem to us
novel and plausible, have been tested before, not once but many times and in
innumerable guises; and discovered to be, at great human cost, wholly false.

--Paul Johnson

----- Original Message ----- 
From: "Jeff Todd" <[EMAIL PROTECTED]>
To: "RollTideFan-The University of Alabama Athletics Discussion List"
<[EMAIL PROTECTED]>
Sent: Thursday, April 29, 2004 10:41 PM
Subject: Re: [RollTideFan] Off season - again...


Devo,

Every positive integer is a multiple of 9 plus the sum of its
digits.

Here is why.  Take 7843.  That's equal to

7�1000 + 8�100 + 4�10 + 3 which equals

7�(999 + 1) + 8�(99 + 1) + 4�(9 + 1) + 3 which equals

7�999 + 7�1 + 8�99 + 8�1 + 4�9 + 4�1 + 3 which equals

7�999 + 7 + 8�99 + 8 + 4�9 + 4 + 3 which equals

(7�999 + 8�99 + 4�9) + (7 + 8 + 4 + 3) which equals

9(7�111 + 8�11 + 4) + (7 + 8 + 4 + 3) which equals

a multiple of 9 + the sum of the digits.

Now when the number is rearranged, that number too is a multiple of 9
plus the sum of its digits.

Since the sum of the digits is the same no matter how the digits are
rearranged, when you subtract you get a multiple of 9 because the sum
of the digits cancel and leave the difference of two multiples of 9,
which is a multiple of 9.

Since the result must be a multiple of 9, the sum of its digits must
also be a multiple of 9.  Now you are given all the digits but one,
so you add all the digits but one, and that missing digit must be
just enough to add to the sum of the other digits to make a multiple
of 9.

7843 = multiple of 9 + (7+8+4+3)
4387 = multiple of 9 + (4+7+8+3)
--------------- subtract these
3456 = multiple of 9 - multiple of 9 + (7+8+4+3) - (4+7+8+3) =

a multiple of 9 + 0 =

a multiple of 9

That multiple of 9 is also a multiple of 9 plus the sum of its
digits.  Therefore the sum of its digits must also be a multiple of
9.

Suppose the person circles the 5 and gives you the three digits
sqrambled as 4,6,3.  You know the sum of the digits must be a
multiple of 9.  You add 4+6+3 and get 13.  The next multiple of 9 is
18, so you know the circled digit must be 18-13 or 5.

Gimme a dollar and I'll tell you how I figured that out. Gimme an extra
dollar
and I'll tell you how long it took me.

Slef E. (The *E* stands for arithmagician)

----- Original Message ----- 
From: "Devan Orange" <[EMAIL PROTECTED]>
To: "'RollTideFan-The University of Alabama Athletics Discussion List'"
<[EMAIL PROTECTED]>
Sent: Thursday, April 29, 2004 10:02 AM
Subject: [RollTideFan] Off season - again...


> Everyone has to try this....I am now in the phase where I am trying to
> figure it out....
>
> http://digicc.com/fido/
>
> DevO
>
>
>
>
>
>
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