On Mon, July 30, 2007 10:37, Jan Kiszka wrote:
> Nadym Salem wrote:
>> On Thu, July 26, 2007 14:05, Nadym Salem wrote:
>>> On Thu, July 26, 2007 13:55, Jan Kiszka wrote:
>>>> Nadym Salem schrieb:
>>>>> Hi,
>>>>> I have a master being connected to several clients using TDMA. I have
>>>>> the
>>>>> need to include one of the clients on the same machine as the master,
>>>>> communicating via ethernet.
>>>>> Thinking of the net as a logical ring, I see the problem of having to
>>>>> interfaces on the master now. Do I get two rings in that case ? And
>>>>> if
>>>>> so,
>>>>> is there a way to avoid that, since my clients have to be
>>>>> synchronous.
>>>> I don't get your scenario yet. I assume it's still IP-less, using
>>>> packet
>>>> sockets, right? What is your precise problem with the rtloopback
>>>> device
>>>> for local delivery?
>>> Right assumed, still the same scenario. Using the loopback device I
>>> would
>>> have two devices on the master. If I want to include one of the slaves
>>> on
>>> the same machine as the master, how could I include the Slave into the
>>> same TDMA "ring" ? My idea would be, to create a new rtethx device on
>>> the
>>> same network adapter. But I have no further idea how to solve that
>>> situation.
>>> If the scenario is still unclear, I could try to create a small picture
>>> ;)
>>
>> Bringing it up again.
>
> Still no clue what your precise problem is, but here are some blind
> comments: It doesn't matter regarding TDMA master/slave where the
> application is running. You have the same TDMA API (via RTDM device
> TDMA<n>) on all nodes, thus you can sync also locally on the master
> clock. On the other hand RTmac/TDMA will not work over loopback, thus
> you don't get anything like "two rings".

The only thing I want is a master and a slave on the same machine, with
additional slaves over ethernet. But I have no idea how to configure that.

If I configure a master over rteth0 and want to configure a slave now the
resource is busy. But I think I have to configure a slave anyhow, don't I
?

Greets, Nadym


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