That doesn't preserve the format, though.
Variation on the prior theme, allows any non-digit spacer, and ensures the
length of the input matches - no excess before or after.
> rx = /^\d{2}(.?)\d{2}\1\d{2}$/
=> /^\d{2}(.?)\d{2}\1\d{2}$/
> #test1: all should pass
* ['234567', '23 45 67', '23a45a67'].all?{|s| s=~rx}
=> true
> #test2; none should pass
* ['23 4567', '23-45 67', '23a45a67a9'].any?{|s| s=~rx}
=> false
James Mason
Systems Administrator/Safety & Environmental Director
Yamato Engine Specialists
360-306-5017
On Wed, Aug 27, 2008 at 3:58 PM, osagie uwaifo <[EMAIL PROTECTED]>wrote:
> I dont know about which is better. You can try this. It would only take out
> the numbers and leave out any other characters
>
> self.credit_card = credit_card.gsub(/[^0-9]/, '')
>
> Thanks,
> Osagie Uwaifo
>
>
> On Wed, Aug 27, 2008 at 1:09 AM, miga <[EMAIL PROTECTED]> wrote:
>
>>
>>
>>
>> On Aug 26, 11:35 pm, "raul parolari" <[EMAIL PROTECTED]> wrote:
>> > > xx?xx?xx where x is a digit and ? may be either nothing, blank, or
>> dash,
>> >
>> > but no mix between them.
>> >
>> > So the '?' in a particular string has the same value. Then, a simpler
>> > regexp is:
>> >
>> > re = /\A \d{2}([- ]?) \d{2}\1 \d{2} \Z/x
>> I did not know this particularity of '?'. Thank you very much.
>>
>>
>>
>>
>
> >
>
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