I'm not sure I understand how these 2 are identical. Former one is a
constructor function (with properties like "prototype", "subclasses",
"superclass"), while latter one is a "prototype" object (with all the
shared "instance" methods).
As far as mixins and inheritance, I would do something like this:
var Predator = Class.create({
hunt: function() {
return this.name + ' is hunting';
}
});
var WaterPredator = Class.create(Predator, {
hunt: function($super) {
return $super() + ' under water';
}
})
var Shark = Class.create({
initialize : function(name) {
this.name = name;
},
speak: function(msg) {
return this.name + ': ' + msg;
}
})
// Create a temporary class and blend both prototypes in:
var MixedIn = Class.create(WaterPredator, Shark.prototype);
new MixedIn('Sharkie').name; // "Sharkie"
new MixedIn('Sharkie').speak('Hello underwater world'); // "Sharkie:
Hello underwater world"
new MixedIn('Sharkie').hunt(); // "Sharkie is hunting under water"
Best,
kangax
On Apr 25, 7:06 am, Mike Rumble <[EMAIL PROTECTED]> wrote:
> > I don't see how "var d = new A(B); " is "chunkier" than "var e = new
> > A(new (B));" : )
>
> I guess it's a matter of taste then. I prefer Object.extend(this, obj)
> to Object.extend(this, obj.prototype), just wanted to know if there
> was really any difference in the two different approaches, and for the
> record both function identically.
>
> > Am I correct that you want to extend instance with methods, and
> > preserve their (methods') inheritance?
>
> Yeah that's spot on.
>
> On Apr 23, 10:53 pm, kangax <[EMAIL PROTECTED]> wrote:
>
> > Am I correct that you want to extend instance with methods, and
> > preserve their (methods') inheritance?
>
> > - kangax
>
> > On Apr 23, 7:22 am, Mike Rumble <[EMAIL PROTECTED]> wrote:
>
> > > Hello,
>
> > > I can't make my mind up over some finer points of an API design and
> > > would appreciate any feedback on my code. Hopefully this example is
> > > clear...
>
> > > var A = Class.create({
> > > initialize : function(obj){
> > > Object.extend(this, obj)
> > > }
>
> > > });
>
> > > var B = {
> > > method : function(){
> > > ....
> > > }
>
> > > };
>
> > > var C = {
> > > method: function(){
> > > ....
> > > }
>
> > > };
>
> > > var d = new A(B);
> > > var e = new A(C);
>
> > > On initialization each instance of class A is extended with methods
> > > from a separate object via Object.extend. I've chosen not to use
> > > Class#addMethods because each instance of can be extended with a
> > > different object, and therefore the prototype chain of class A should
> > > remain unaffected.
>
> > > So for so good.
>
> > > However I'm looking to use this taking advantage of Prototype's
> > > inheritance features for the extension objects. I've currently got
> > > something that looks like this...
>
> > > var A = Class.create({
> > > initialize : function(obj){
> > > Object.extend(this, obj.prototype)
> > > }
>
> > > });
>
> > > var B = Class.create({
> > > method : function(){
> > > ....
> > > }
>
> > > })
>
> > > var C = (B, {
> > > method: function($super){
> > > $super();
> > > }
>
> > > };
>
> > > var d = new A(B);
> > > var e = new A(C);
>
> > > It works OK but feels a little clunky. To me it would make more sense
> > > to do something like this...
>
> > > var A = Class.create({
> > > initialize : function(obj){
> > > Object.extend(this, obj)
> > > }
>
> > > });
>
> > > var B = Class.create({
> > > method : function(){
> > > ....
> > > }
>
> > > })
>
> > > var C = (B, {
> > > method: function($super){
> > > $super();
> > > }
>
> > > };
>
> > > var d = new A(new (B));
> > > var e = new A(new (C));
>
> > > Anybody got any strong opinions on which approach is best?
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