Thanks much, It worked.
On Apr 28, 3:39 pm, kangax <[EMAIL PROTECTED]> wrote:
> $$('span.' + currentHighlightGroup);
>
> // or
>
> $$('span').findAll(function(el){
> return el.hasClassName(currentHighlightGroup)
>
> });
>
> // the latter one will actually be much slower...
>
> - kangax
>
> On Apr 28, 2:42 pm, "[EMAIL PROTECTED]"
>
> <[EMAIL PROTECTED]> wrote:
> > Hi all,
>
> > I want the $$() method to take the selector as an variable. See
> > below, I am trying to pass the class name as javascript variable so I
> > can write a generic function in my application but $$() returns
> > nothing for the following line
>
> > var currentHightLightGroup ="amountsFields";//This one comes as a
> > function parameter
> > $$('span[class=\''+currentHightLightGroup+'\']')
> > -> returns nothing.
>
> > Any help is much appericated.
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