The answer is this (I was close, just needed to be more specific):
new Ajax.Updater('fruits', 'calculator2.php', { method: 'post',
parameters: form1.serialize() });
On May 13, 6:43 pm, McBlaue <[EMAIL PROTECTED]> wrote:
> I also have tried this but no go:
>
> new Ajax.Updater('fruits', 'calculator2.php', { method: 'post',
> parameters: Form.serialize(this) });
>
> On May 13, 4:02 pm, McBlaue <[EMAIL PROTECTED]> wrote:
>
> > Hi I'm a newbie to AJAX and prototype and am writing a simple
> > application that calculates some figures in php given some variables
> > from a form, and display the outcome in a DIV. I can get it to
> > function using a single parameter like this:
>
> > function doSums() {
> > new Ajax.Updater('fruits', 'calculator2.php', { method: 'post',
> > parameters: salary=$('salary').serialize(true) });
> > return false;
> > }
>
> > but I can't pass more than 1 form element. I have tried:
>
> > parameters: salary=$('salary'), age=$('age').serialize(true)
>
> > and
>
> > parameters: $F('salary'), $F('age').serialize(true)
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