new Ajax.Request
not
Ajax.Response
On May 21, 1:55 pm, gabriel1836 <[EMAIL PROTECTED]> wrote:
> Here's the new code:
>
> var span = 'totalViews' + video_id;
> var params = {'video_id': video_id};
>
> Ajax.Response('ajaxHandler.php',
> {
> method: 'post',
> parameters: params,
> onSuccess: function(transport)
> {
> var count =
> transport.responseText;
>
> $('totalViews' +
> video_id).innerHTML = count;
>
> Mediabox.open(video_url, '',
> 'mediabox[480 380]');
> },
> onFailure: function()
> {
> alert('I Fudged Things.');
> }
> }
> );
>
> Still returns the same this.initialize has no properties error. Any
> other ideas?
>
> On May 21, 11:36 am, blechler <[EMAIL PROTECTED]> wrote:
>
> > var span = 'totalViews' + video_id;
> > var params = {'video_id' : video_id);
>
> > new Ajax.Request('trackVideo.php', {
> > method: 'post',
> > parameters: params,
> > onSuccess: function(transport) {
> > var count = transport.responseText;
> > $('span').innerHTML = count;
> > Mediabox.open(video_url, '', 'mediabox[480 380]');
> > },
> > onFailure: function() {
> > alert('I Fudged Things.');
> > }
>
> > });
>
> > Try that.
>
> > On May 21, 1:28 pm, gabriel1836 <[EMAIL PROTECTED]> wrote:
>
> > > Hi All,
>
> > > I'm a super newbie with Prototype and am trying to implement my first
> > > solution using it.
>
> > > This is my code:
>
> > > var span = 'totalViews' + video_id;
> > > var params = 'video_id=' + video_id;
>
> > > Ajax.Response('trackVideo.php',
> > > {
> > > method: 'post',
> > > parameters: params,
> > > onSuccess: function(transport)
> > > {
> > > var count =
> > > transport.responseText;
>
> > > $('span').innerHTML =
> > > count;
>
> > > Mediabox.open(video_url,
> > > '', 'mediabox[480 380]');
> > > },
> > > onFailure: function()
> > > {
> > > alert('I Fudged Things.');
> > > }
> > > }
> > > );
>
> > > However, when I try to execute the code I get this error
> > > "this.initialize has no properties". It appears to be related to this
> > > function call this.initialize.apply(this, arguments); at line 48 in
> > > Prototype.js.
>
> > > Any help offered would be greatly appreciated.
>
> > > Thanks.
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