Off the top of my head, inside of your onDrop handler, call
.positionedOffset() on the element and the drop container and see how much
they differ:
Droppables.add(target, {
onDrop: function(element) {
var elementOffset = element.positionedOffset();
var targetOffset = target.positionedOffset();
var diffX = targetOffset.left - elementOffset.left;
var diffY = targetOffset.top - elementOffset.top;
....
}
});
On Thu, May 29, 2008 at 6:53 AM, Wyerarch <[EMAIL PROTECTED]> wrote:
>
> Hi All,
>
> I am trying to develop a dynamic form creator application, whereby we
> can drag objects from a "palette" and drop them onto a "form" to build
> the design of our form.
>
> To achieve this, when I have dragged the object, and dropped it onto
> the "form" area, I want to get the position of where the object was
> dropped.
>
> I have a droppable area:
>
> Droppables.add('dropArea', {onDrop:addItem});
>
> And a method that calls a webservice via AJAX:
>
> function addItem(element, dropon, event)
> {
> var s = element.id;
> //
> element.width,element.height,element.top,element.left,
> AJAXDDtest.DBAccess.InsertField(s,element.innerHTML,0,0,0,0,
> onGetDataComplete, onGetDataTimeOut);
> }
>
> Essentially, i want to get the width, height, top, and left of the
> element that was dropped - is this possible? I have tried looking
> around the sciptaculous wiki, but I can't find a DOM for the
> droppables, unless someone can point me in the right direction?
>
> I am building the draggables as follows:
>
> var aproducts = document.getElementsByClassName('box');
> for (var i = 0; i < aproducts.length; i++) {
> new Draggable(aproducts[i].id, {ghosting:false, revert:true,
> onEnd:endItem})
> }
>
> Any help would be greatfully received,
>
> Thanks,
>
> James.
> >
>
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