You can also do:

$aMenus.each(Element.hide);

this way, each item of the array will get passed into a Element.hide 
() call,
no need for the extra inline function definition.

Best,
Thomas

Am 19.10.2006 um 00:00 schrieb Keith Davis:

>
> Never mind. It was just a typo. It should have been  
> submenu_reporting. Duh.
>
> -----Original Message-----
> From: [email protected]
> [mailto:[EMAIL PROTECTED] On Behalf Of Christophe
> Porteneuve
> Sent: Wednesday, October 18, 2006 4:34 PM
> To: [email protected]
> Subject: [Rails-spinoffs] Re: Using array.each with Element.hide
>
>
> Hey Keith,
>
> First, you might want not to name your variables with leading $'s.   
> It's
> not idiomatic JS.  Basically, $-vars are the realm of PHP :-)   
> Perusing your
> script a first time, I was confused as to the language context :-D
>
> Keith a écrit :
>>                      function ShowMenu($sMenu){
>>
>>                              var $aMenus = new Array();
>>                              $aMenus = ['submenu_reports',
> 'submenu_forms',
>> 'submenu_tickets'];
>
> First, you can put this in one line: your new Array() never gets used.
>
>>                              $aMenus.each( function($s){Element.hide($s);
> })
>>
>>                              Element.show($sMenu);
>>
>>                      }
>>
>> The error I get it is style is null or not an object. If I swap out
>> Element.hide for alert, it works fine.
>
> Where do you get this?  The final show line?  Then we'd have to  
> know what is
> being passed to your ShowMenu function...  If it's in the anonymous  
> function
> (hide calls), double-check the IDs in your array against the actual  
> DOM of
> your page.
>
>
> --
> Christophe Porteneuve a.k.a. TDD
> "[They] did not know it was impossible, so they did it." --Mark Twain
> Email: [EMAIL PROTECTED]
>
>
>
> >

--
Thomas Fuchs
wollzelle

http://www.wollzelle.com

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