Yes.

Use sortable.sequence to get the order of the ids. (this is probably a
string, so convert it to an array with split or similar).
Then use $(array) to find the elements (i think you can do this).
Then pluck/use select to get the value you want to sort. (this should be an
array)
Now you need to get a hash id-name, so you'll probably want to do something
fancy with hashes so you end up with pairs.
Now sort the hash (again I think there's a method)...
now extract the ids back from your sorted hash and use sortable.sort to set
the order of the elements...

Well.. thats a rundown of what i'd try first.
Read api docs and compromise/mix match methods as you see fit.

Gareth



On 8/1/07, Tarscher <[EMAIL PROTECTED]> wrote:
>
>
> Hi all,
>
> I have 3 lists containing users (users and groups). You can move the
> users between the lists. The user are ordered alphabetically in the
> list.
>
> I know it is possible to move the users between the lists but is it
> also possible that when you drop a user in a list it get placed in the
> correct alphabetical place?
>
> Eg:
>
> Group 1
> - Jan
> - Tom <-- drag
> Group 2
> - Kevin
> - Nina
>
> Dragging Tom to group 2
>
> Group 1
> - Jan
> Group 2
> - Kevin
> - Nina
> - Tom
>
> Regards,
> Stijn
>
>
> >
>

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