Ken Snyder for the win! That is what i have been looking for, the non-
Ruby scoop.
On Dec 20, 2:38 pm, Ken Snyder <[EMAIL PROTECTED]> wrote:
> From a non-Ruby guy, here is the scoop:
>
> Ruby has a keyword "super" that is available within all methods. It
> allows you to call the parent function of the same name.
>
> In php I write:
> public function mymethod($arg) {
> parent::mymethod($arg); // equivalent to Ruby super($arg)
>
> }
>
> So this JS implementation basically has $super refer to the parent
> method of the same name so you can call $super()
>
> "$super" is used instead of "super" because "super" is a reserved word
> in JS.
>
> The sugar is that extended classes automagically pass a reference of the
> parent function into child function only for methods that have a $super
> argument (detected when the child function is converted to a string with
> toString()).
>
> - Ken Snyder
>
> PS. great interjection of "confuzzled"!
>
> Matt Foster wrote:
> > Greetings,
>
> > I had a question about the $super argument that I wasn't
> > able to find in documentation, searching etc. What exactly is the
> > $super argument. Is it a reference to the super class's prototype
> > function? Or is it an instantiated object of the super class that is
> > passed to the subclass's method?
>
> > I am completely confuzzled on this one, my typical method of just
> > reading the source has left me worse off. Can anyone explain this
> > concept or perhaps point me to a resource which properly defines it?
>
> > Thanks in advance,
> > Matt
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